According to the great well-known Euler’s formula: eiθ=cos⁡θ+isin⁡θ Let θ=π/2, then: eiπ/2=cos(π/2)+isin(π/2)=0+i×1=i Now, doing a substitution i with eiπ/2: ii=(eiπ/2)i=(eπ/2)i2=e−π/2=0.207879… How beautiful!

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